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4 Measurement of Biosignals and Analog Signal Processing
Fig. 4.39: Characteristic functions K(Ω) = ϵΩn (left) and magnitudes of the transfer functions of the
associated normalised low-pass filters up to 4th order for ϵ = 1 (right).
and after Equation 4.19 results in:
|A(jΩ)|2 =
1
1 + ϵ2 ⋅Ω2n .
(4.21)
At the normalised passband cut-off frequency Ω= 1, the characteristic function K(Ω)
has the value ϵ and is otherwise always smaller in the passband. The tolerance scheme
must therefore have this maximum value. At ϵ = 1 the magnitude of the transfer
function |AnTP(Ω= 1)| = 1/√2 ≈0.707. This corresponds to an attenuation a =
−20⋅log(|AnTP|) of 3 dB (cf. Figure 4.39). If one now extends according to Equation 4.72
the normalised frequency Ωto the complex frequency P := Σ + jΩ, then starting from
Σ = 0 for the product GnTP(P) := AnTP(P) ⋅AnTP(−P) we obtain:
GnTP(P) =
1
1 + K(P/j)2 =
1
1 + ϵ2( P
j )
2n =
1
1 + ϵ2 (e−jπ/2P)2n .
(4.22)
Zeros of GnTP(P) are not present. The pole places Pk of GnTP(P) are at the zeros of the
denominator, i.e..
1 + K(P±k/j)2 = 0
(4.23)
respespectively
K(P±k/j) = ±j
(4.24)
and have the values (cf. also [68]):
P±k = ejπ/2 (−1
ϵ2 )
1/2n
= ej(π/2±(π+k⋅2π)/2n)
n√ϵ
,
k = 0, . . . , n −1 .
(4.25)
Since the amount of these poles always have the same value of 1/
n√ϵ, the poles all
lie on a circle (cf. Figure 4.37, for ϵ = 1). Now that the poles and zeros of GnTP(P) are